Question

求几道分解因式的答案（需过程）1、3x^2+19xy+6y^22、ax^n+1-ax^n-20ax^n-13、(1-x^

Answer 1

1、3x^2+19xy+6y^2

=3x^2+18xy+xy+6y^2

=3x(x+6y)+y(x+6y)

=(x+6y)(3x+y)

2、ax^n+1-ax^n-20ax^n-1

=ax^(n-1)(x^2-x-20)

=ax^(n-1)(x-5)(x+4)

3、(1-x^2)(1-y^2)+4xy

=x^2y^2-x^2-y^2+1+2xy+2xy

= (x^2y^2+2xy+1)-(x^2-2xy+y^2)

=(xy+1)^2-(x-y)^2

=(xy+x-y+1)(xy-x+y+1)