我要列式计算甲乙两堆煤共120吨,现在两堆煤中各运走15吨,剩下的甲堆煤是乙堆煤的5份之4,乙堆煤原来有多少吨?

1个回答

  • 设甲为x,乙为y,

    x+y=120 ①

    (x-15)/(y-15)=4/5 ②

    由得x=120-y ③

    把③带入②得(120-y-15)/(y-15)=4/5

    (105-y)*5=(y-15)*4

    525-5y=5y-60

    10y=585

    y=58.5

    x=120-y=120-58.5=61.5