Question

有一有机物A,蒸汽的密度是同条件下空气密度的3.24倍,此物质中碳元素的质量分数为76.6%,氢元素的质量分

Answer 1

M=29*3.24=94

n(C)=(94*76.6%)/12=6

n(H)=(94*6.4%)/1=6

n(O)=(94*17%)/16=1

A的分子式C6H6O 结构简式:苯酚 C6H5OH.

C6H6O + NaOH ------C6H5-ONa +H2O

C6H5-ONa + HCl -------C6H5OH +NaCl

C6H5OH +3Br2 --------C6H2Br3--OH (2.4.6-三溴苯酚） + 3HB