(1)、图中与∠COE互补的角有:∠EOD,∠BOF;
(2)按图条件应该是:如果∠AOC=1/4∠EOF
∵∠AOE=∠COF=90°
∠EOF=∠AOE+∠COF-∠AOC=90°×2-∠AOC
又∵∠AOC=1/4∠EOF
∴5∠AOC=180°
∴∠AOC=180/5=36°
(1)、图中与∠COE互补的角有:∠EOD,∠BOF;
(2)按图条件应该是:如果∠AOC=1/4∠EOF
∵∠AOE=∠COF=90°
∠EOF=∠AOE+∠COF-∠AOC=90°×2-∠AOC
又∵∠AOC=1/4∠EOF
∴5∠AOC=180°
∴∠AOC=180/5=36°