sinx +siny=1/3 cosx+cosy=1/4 求tan(x+y)和sin(x+y)

2个回答

  • sinx+siny=sin((x+y)/2+(x-y)/2)+sin((x+y)/2-(x-y)/2)=1/3

    cosx+cosy=cos((x+y)/2+(x-y)/2)+cos((x+y)/2-(x-y)/2)=1/4

    根据三角函数公式化简得

    2cos[(x-y)/2]sin[(x+y)/2]=1/3

    2cos[(x+y)/2]cos[(x-y)/2]=1/4

    tan[(x+y)/2]=4/3

    cos[(x+y)/2]=+-3/5

    sin[(x+y)/2]=+-4/5(由于tan>0,sin,cos 必须同号)

    sin(x+y)=2(12)/25 =24/25 (cos[(x+y)/2],sin[(x+y)/2]同号,乘积为正)

    cos(x+y)=2(cos[(x+y)/2])^2-1=-7/25

    tan(x+y)=sin(x+y)/cos(x+y)=-24/7