.已知实数abc满足a+b+2c=1,a2+b2+6c+3/2=0,求abc的值
1个回答
a2+b2+6c+3/2-3(a+b+2c-1)=a²+b²-3a-3b+9/2=(a-3/2)²+(b-3/2)²=0
a=b=3/2
2c=1-2*3/2=-2,c=-1
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