a)limAC=19/18;
q→∞
b)MC=dTC/dq=d(AC*q)/dq
=d[(324q/√q^2+35)+5+19q/18]/dq
=11340/(q^2+35)^(3/2)+19/18,
q=17,MC=3;
c)MR=P=△TR/△q=275/(18-17)=275,
when q=17,MC
a)limAC=19/18;
q→∞
b)MC=dTC/dq=d(AC*q)/dq
=d[(324q/√q^2+35)+5+19q/18]/dq
=11340/(q^2+35)^(3/2)+19/18,
q=17,MC=3;
c)MR=P=△TR/△q=275/(18-17)=275,
when q=17,MC