2H2(g)+O2=2H2O(l)△H=-571.6kj/mol CO(g)+1/2O2(g)=CO2(g)△H=-283kj/mol 2mol 36g 571.6kJ 1mol 283kJ
x 3.6g 57.16kJ y (113.74-57.16)kJ
解得x=0.2mol,y=0.2mol,即x:y=1:1
2H2(g)+O2=2H2O(l)△H=-571.6kj/mol CO(g)+1/2O2(g)=CO2(g)△H=-283kj/mol 2mol 36g 571.6kJ 1mol 283kJ
x 3.6g 57.16kJ y (113.74-57.16)kJ
解得x=0.2mol,y=0.2mol,即x:y=1:1