设甲原速为x,乙原速为y
400/(x+y)+400y/[(x+y)(x+2)]=24 ①
400/(x+y)+400x/[(x+y)(y-2)]=24 ②
①-②有:
y/(x+2)=x/(y-2)
∴x^2+2x=y^2-2y
(x+1)^2=(y-1)^2 ,y>2
∴y=x+2
代入①有:400/(2x+2)+400(x+2)/[(2x+2)(x+2)]=24
∴400/(x+1)=24
∴x=47/3
即甲原来的速度为47/3 m/s
设甲原速为x,乙原速为y
400/(x+y)+400y/[(x+y)(x+2)]=24 ①
400/(x+y)+400x/[(x+y)(y-2)]=24 ②
①-②有:
y/(x+2)=x/(y-2)
∴x^2+2x=y^2-2y
(x+1)^2=(y-1)^2 ,y>2
∴y=x+2
代入①有:400/(2x+2)+400(x+2)/[(2x+2)(x+2)]=24
∴400/(x+1)=24
∴x=47/3
即甲原来的速度为47/3 m/s