∵3AC=2AB
∴AC=2AB/3,BC=AB/3
∵D是AB的中点,E是CB的中点
∴AD=BD=½AB,CE=½BC=1/6AB
∴DC=AC-AD=2/3AB-1/2AB=1/6AB
∴DE=DC+CE=1/6AB+1/6AB=1/3AB
∵DE=6
∴AB=6×3=18
AD:CB=1/2AB:1/3AB=1/2:1/3=3:2
∵3AC=2AB
∴AC=2AB/3,BC=AB/3
∵D是AB的中点,E是CB的中点
∴AD=BD=½AB,CE=½BC=1/6AB
∴DC=AC-AD=2/3AB-1/2AB=1/6AB
∴DE=DC+CE=1/6AB+1/6AB=1/3AB
∵DE=6
∴AB=6×3=18
AD:CB=1/2AB:1/3AB=1/2:1/3=3:2