(3x^2+9x+7)/(x+1)-(2x^2+4

4个回答

=（3x^2+9x+7)（x+1）/（x^2-1）-（2x^2+4x-3）(x-1)/（x^2-1）-（x^3+x+1)/(x^2-1)
=（3x^3+12x^2+16x+7）/（x^2-1）-（2x^3+2x^2-7x+3）/（x^2-1）-（x^3+x+1)/(x^2-1）
=（10x^2+22x+3）/(x^2-1）

(3x^2+9x+7)/(x+1)-(2x^2+4x-3)/(x-1)-(x^3+x+1)/(x^2-1)=
2（x-2)+2=x+1 2（x-2)-3(4x-)=9(1-x) 7（2x-1)-3(4x-1)=4(3x+2)-1
解方程(3x^2+9x+7)/(x+1)-(2x^2+4x-3)/(x-1)-(x^3+x+1)/(x^2-1)=0
巧算(3x^2+9x+7)/(x+1)-(2x^2-4x-3)/(x-1)-(x^2+x+1)/(x^2-1)
线性方程组为：x1-x2-5x3+4x4=2 2x1-x2+3x3-x4=1 3x1-2x2-2x3+3x4=3 7x1
x1+x3+x4=7 x2+x3+x4=6 x2+x1+x4=8 x2+x1+x3=9 求x1 x2 x3 x4 是多少
计算:再问一题：(3x^2+9x+7)/(x+1)-(2x^2-4x+3)/(x-1)-(x^3+x+1)/(x^2-1
（3x^2+9x+7）/（x+1）-（2x^2-4x+3)/(x-1)-(x^3+x+1)/(x^2-1)是不是错了?
(x1-x2+4x3-2x4=0;x1-x2-x3+2x4=0;3x1+x2+7x3-2x4=0;x1-3x2-12x3
3道解方程1.2(2-x)+3(4x-2)=7(x+4)2.2(x-2)+3(2x-1)=9(x-1)3.10*(2-x