作B′M′∥C′D′,C′M′⊥B′M′于点M′.
粉笔的半径是6mm.则边长是6mm.
∵∠M′B′C′=60°
∴B′M′=B′C′•cos60°=6× 12=3.
边心距C′M′=6sin60°=3 3mm.
则图(2)中,AB=CD=11×3 3=33 3mm.
AD=BC=5×6+5×12+3=93mm.
则周长是:2×33 3+2×93=66 3+186≈300mm.
故答案是:300mm.
作B′M′∥C′D′,C′M′⊥B′M′于点M′.
粉笔的半径是6mm.则边长是6mm.
∵∠M′B′C′=60°
∴B′M′=B′C′•cos60°=6× 12=3.
边心距C′M′=6sin60°=3 3mm.
则图(2)中,AB=CD=11×3 3=33 3mm.
AD=BC=5×6+5×12+3=93mm.
则周长是:2×33 3+2×93=66 3+186≈300mm.
故答案是:300mm.