Question

因式分解 1、 x²-(x-y)² 2、 x²-ax+ay-y²

Answer 1

1)

原式=[x+(x-y)][x-(x-y)]

=(2x-y)y

=y(2x-y)

2)

原式=x²-y²-ax+ay

=(x+y)(x-y)-a(x-y)

=(x-y)(x+y-a)