Question

((3x-7)^2-(x+5)^2)/(4x-24).2,((x^2+1)^2-4x(x^2+1)+4x^2)/(x-1

Answer 1

((3x-7)^2-(x+5)^2)/(4x-24).

=(3x-7+x+5)(3x-7-x-5)/(4x-24)

=(4x-2)(2x-12)/(4x-24)

=4(2x-1)(x-6)/4(x-6)

=2x-1

((x^2+1)^2-4x(x^2+1)+4x^2)/(x-1)^2

=[(x^2+1)-2]^2/(x-1)^2

=(x^2-1)^2/(x-1)^2

=(x-1)^2(x+1)^2/(x-1)^2

=(x+1)^2

=x^2+2x+1