Question

已知碳酸钙和另一种物质组成的混合物含碳量大于12%,则另一种物质可能是：

Answer 1

C

c 12

--- = --- = 12%

Caco3 100

c 12

--- = --- < 12%

Na2co3 106

c 12

--- = --- = 12%

KHco3 100

c 12

--- = --- > 12%

Mgco3 84

c 12

--- = --- < 12%

K2co3 138

Mgco3=碳酸镁

所以是C.

请参考.(等号前后的---是分数线)