某射手每次击中目标的概率为0.28,今连续射击10次,其最可能击中的次数是多少?

1个回答

  • 击中0次的概率为:C(10,0)*0.72^10≈0.037439062

    击中1次的概率为:C(10,1)*0.28*0.72^9≈0.145596354

    击中2次的概率为:C(10,2)*0.28^2*0.72^8≈0.254793619

    击中3次的概率为:C(10,3)*0.28^3*0.72^7≈0.26423042 最大

    击中4次的概率为:C(10,4)*0.28^4*0.72^6≈0.17982348

    击中5次的概率为:C(10,5)*0.28^5*0.72^5≈0.083917624

    击中6次的概率为:C(10,6)*0.28^6*0.72^4≈0.027195526

    击中7次的概率为:C(10,7)*0.28^7*0.72^3≈0.00604345

    击中8次的概率为:C(10,8)*0.28^8*0.72^2≈0.000881337

    击中9次的概率为:C(10,9)*0.28^9*0.72≈0.000076

    击中10次的概率为:C(10,10)*0.28^10≈0.000003

    所以,连续射击10次,其最可能击中的次数是3次,其次是2次.