Question

解分式方程：x²+ x分之7+ x²-x分之1= x²-1分之6

Answer 1

7/(x²+x)+ 1/(x²-x)= 6/(x²-1)

7/[x(x+1)]+1/[x(x-1)]-6/[(x+1)(x-1)]=0

[7(x-1)+(x+1)-6x]/[x(x+1)(x-1)]=0

即 7(x-1)+(x+1)-6x=0

7x+x-6x-6=0

2x=6

x=3