1/3ab(2a^2-ab+6b^2)
2个回答
1/3ab(2a^2-ab+6b^2)
=1/3ab*2a^2-1/3ab*ab+1/3ab*6b^2
=2/3a^3b-1/3a^2b^2 +2ab^3
相关问题
①(-3ab)(2a^b+ab-1)②(6ab^3+2ab^2-3ab+1)(-2a^b)
6ab-3【3b^2-(a^2-2ab)+1] a=-2 b=-1/3
计算 (a^2b-ab-a+1)/(ab^2+3ab-b-3)÷(a^2+a_2)/(b^2+b-6)
1/2a^2b+(5a^2b-ab^2)-(-1/4a^2b+3a)-(3ab^2-6)
计算:(1)a^-2b^-3·(-3a^-1b^2)÷6a^-4b^-2 (2)(3ab)^-3(2ab^-1)^-2
已知(a+b)2+|2b-1|=0,则 6ab-2ab-3(ab-1)=______.
已知(a+b)2+|2b-1|=0,则 6ab-2ab-3(ab-1)=______.
(1/3a^2b-1/6ab)/( )=3ab
已知a+b=1,ab=-2求-(2ab-6a-2a)-3(ab+1/3a-b)的值
5a3b•(-3b)2+(-6ab)2•(-ab)-ab3•(-4a)2.