【参考答案】
由a²+2a-8=0
得：a²+2a=8
a(a+2)²-a(a-3)(a-1)+3(5a-2)
=a(a²+4a+4)-a(a²-4a+3)+15a-6
=a³+4a²+4a-a³+4a²-3a+15a-6
=(a³-a³)+(4a²+4a²)+(4a-3a+15a)-6
=8a²+16a-6
=8(a²+2a)-6
=8×8-6
=58
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已知实数a满足a^2+2a-8=0求a(a+2)^2-a(a-3)(a-1)+3(5a-2)的值
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