Question

计算题和解不等式组过程谢谢计算题(-3)^0-3√27+丨1-√2丨+1/√3+√2-2sin60°解不等式组①x-2/

Answer 1

解

原式

=1-9√3+√2-1+√3/3+√2-2×(√3/2)

=(1-1-2)+(-9√3+√3/3)+(√2+√2)-√3

=-2+2√2-29√3/3

(x-2)/4≥x

x-2≥4x

x-4x≥2

-3x≥2

x≤-2/3

1-3(x-2)