Question

根号2+3/2=2根号3/21.判断下列各式是否成立：√2+2/3=2√2/3（ ）√3+3/8=3√3/8( ).你发

Answer 1

√[n+n/(n^2 -1)]=n·√[n/(n^2-1)]

(对等号前的式子通分,再整理,就能得到后式)