Question

若a满足不等式组{2(a-1)小于等于3a+1 a/3小于等于(a+1)/4 那么,代数式a^2-6*(a-1/a)/(

Answer 1

=a^2-6*{(a^2-1)/a}*{a/(a-1)}

=a^2-6*{(a-1)*(a+1)/a}*{a/(a-1)}

=a^2-6*(a+1)

=a^2-6a-6

=(a-3)^2-15