√3tan21°*tan39°+tan21°+tan39°=

1个回答

  • tan(a+b)=(tanA+tanB)/(1-tanAtanB)

    (1-tanAtanB)=(tanA+tanB)/tan(A+B)

    tanAtanB)=1-(tanA+tanB)/tan(A+B)

    √3tan21°*tan39°+tan21°+tan39°

    =√3[1-(tan21°+tan39°)/tan(21°+39°)]+tan21°+tan39°

    =√3-√3(tan21°+tan39°)/tan(60°)+tan21°+tan39°

    =√3-√3(tan21°+tan39°)/√3+tan21°+tan39°

    =√3-(tan21°+tan39°)+tan21°+tan39°

    =√3-tan21°-tan39°+tan21°+tan39°

    =√3