Question

请分别写出磷酸钠溶液的物料守恒/质子守恒/电荷守恒三个等式

Answer 1

物料守恒：[Na(+)]=[PO4(3-)]+[HPO4(2-)]+[H2PO4(-)]+[H3PO4]

质子守恒：[H(+)]+[H3PO4]=[OH(-)]+[PO4(3-)]

电荷守恒：[Na(+)]+[H(+)]=[PO4(3-)]+[HPO4(2-)]+[H2PO4(-)]+[OH(-)]

质子守恒不确定,电荷守恒和物料守恒绝对没错