化简如下：
x³-(√2-1)x²-(√2+1)x²+x+(x-√2+1)=0
x²(x-√2+1)-(√2+1)x(x-√2+1)+(x-√2+1)=0
(x-√2+1)[x²-(√2+1)x+1]=0
x-√2+1=0,得：x=√2-1
x²-(√2+1)x+1=0,得：x=[(√2+1)±√(2√2-1)]/2
解方程,（最好用纸写,拍图片,手打也可以接受）
化简如下：
x³-(√2-1)x²-(√2+1)x²+x+(x-√2+1)=0
x²(x-√2+1)-(√2+1)x(x-√2+1)+(x-√2+1)=0
(x-√2+1)[x²-(√2+1)x+1]=0
x-√2+1=0,得：x=√2-1
x²-(√2+1)x+1=0,得：x=[(√2+1)±√(2√2-1)]/2