乙炔合成4-辛酮 (急)谢谢!

1个回答

  • 液氨的条件下 HC≡CH+NaNH2→HC≡CNa;

    HCCNa+C2H5Br→HC≡C-C2H5;(炔所独有的链增长反应)

    HC≡C-C2H5+H2=C4H10;

    C4H10+Br2=C4H9Br;

    HC≡C-C2H5+NaNH2→NaC≡C-C2H5;

    NaC≡C-C2H5+C4H9Br= C2H5-C≡C4H9;

    酸性条件下C2H5-C≡C4H9+H2O(水)+Hg+= C2H5-COC4H9(4 -辛酮);(炔在酸性条件下 Hg+ 时的水解反应涉及原子重排)

    主要的反应:HC≡CH+NaNH2→HC≡CNa;

    HCCNa+C2H5Br→HC≡C-C2H5;

    酸性水溶液:CH3C≡CH+H2O+Hg+=CH3COCH3(丙酮);