因为 f(sin x)=sin [ (4n+1) x ] ,
所以 f(cos x)=f[ sin (x +pi/2) ]
=sin [ (4n+1) (x +pi/2) ]
=sin [ (4n+1) x +2n *pi +pi/2]
=sin [ (4n+1) x +pi/2 ]
=cos [ (4n+1) x ].
因为 f(sin x)=sin [ (4n+1) x ] ,
所以 f(cos x)=f[ sin (x +pi/2) ]
=sin [ (4n+1) (x +pi/2) ]
=sin [ (4n+1) x +2n *pi +pi/2]
=sin [ (4n+1) x +pi/2 ]
=cos [ (4n+1) x ].