分解因式:(x^2-x-2)(x^2-11x+28)+32

2个回答

  • (x^2-x-2)(x^2-11x+28)+32

    =[(x+1)(x-2)]*[(x-4)(x-7)]+32

    =[(x+1)(x-7)]*[(x-4)(x-2)]+32

    =[(x^2-6x)-7]*[(x^2-6x)+8]+32

    =(x^2-6x)^2+(x^2-6x)-56+32

    =(x^2-6x)^2+(x^2-6x)-24

    =(x^2-6x)^2+(x^2-6x)+1/4-97/4

    =(x^2-6x+1/2)^2-97/4

    =[x^2-6x+(1+根号97/2)]*[x^2-6x+(1-根号97/2)]