解1题：
原式=√(10x×10负1次方y×100z)
=√[10x×(y/10)×100z]
=√(100xyz)
=10√(xyz)
解2题：
原式=√(5/3)÷√(7/3)×√(7/5)
=√(5/3÷7/3×7/5)
=√(5/3×3/7×7/5)
=√1
=1
解3题：
原式=[(√3a)/(2b)]×[√(b/a)÷2√(1/b)]
=[1/(2b)÷2]×√[3a×(b/a)÷(1/b)]
=[1/(4b)]×√[3a×(b/a)×b]
=[1/(4b)]×√(3b²)
=[1/(4b)]×b√3
=(√3)/4