1)【(a+1)/(a²-a)+4/(1-a²)】÷(a-1)=

5个回答

  • 1)【(a+1)/(a²-a)+4/(1-a²)】÷(a-1)

    =[a﹙a+1﹚﹙a-1﹚-4﹙a+1﹚﹙a-1﹚]÷(a-1)

    =a﹙a+1﹚-4﹙a+1﹚

    =a²+a-4a-4

    =a²-3a-4

    2)【a-(a²-b²+1)/a】÷【(b-1)/a】×【1/(a+b)】

    =[﹙a²-a²+b²-1﹚/a]×[a/﹙b-1﹚]×[1/﹙a+b﹚]

    =[﹙b+1﹚﹙b-1﹚﹚/a]×[a/﹙b-1﹚]×[1/﹙a+b﹚]

    =﹙b+1﹚/﹙a+b﹚

    3)(2x²-6x)/(x²-9)-(x+3)/(3-x)-(2x+6)/(x²+6x+9)

    =[2x﹙x-3﹚/﹙x-3﹚﹙x+3﹚]+﹙x+3﹚/﹙x-3﹚-2﹙x+3﹚/﹙x+3﹚³

    =2x/﹙x+3﹚-2/﹙x+3﹚+﹙x+3﹚/﹙x-3﹚

    =﹙2x-2﹚/﹙x+3﹚+﹙x+3﹚/﹙x-3﹚

    =﹙2x-2﹚﹙x-3﹚+﹙x+3﹚²/﹙x+3﹚﹙x-3﹚

    =﹙3x²-2x+15﹚/﹙x+3﹚﹙x-3﹚