Question

2a分之1减去a-b分之1乘以（2a分之a-b减去a的平方加上b的平方）,其中a=3减去2根号2,b=3根号2减去3,救

Answer 1

1/2a-1/(a-b)*[(a-b)/2a-a^2+b^2]

=1/2a-1/(a-b)*[(a-b)/2a-(a^2-b^2)]

=1/2a-1/(a-b)*(a-b)/2a+1/(a-b)*(a^2-b^2)

=1/2a-1/(a-b)*(a-b)/2a+1/(a-b)*(a-b)(a+b)

=1/2a-1/2a+(a+b)

=a+b

=3-2√2+3√2-3

=√2