cosxcos( π/6-x)= 1/2[cos π/6+cos( π/6-2x)]= 1/2cos( π/6-2x)+√ 3/4≤﹙ 2+√3﹚/4
cos(x)*cos(π/6-x) 接下来怎么化简
1个回答
相关问题
-
化简cos(π/6+x)+cos(π/6-x)
-
cos(2x-π/3)+cos(2x+π/6)化简
-
sin(π/3-3x)cos(π/3+3x)-cos(π/6-3x)sin(π/6+3x) 化简
-
化简sin2x-cos(2x+π/6)
-
sin(x+π/3)+(tanπ/6)cos(x+π/3) 化简
-
√2sin(x-π/4)+√6cos(x-π/4)化简
-
1.化简f(x)=cosx(asinx-cosx)+cos(π/2-x)cos(π/2-x).2.化简f(x)=4cos
-
函数f(x)=1+cos2x-2sin²(x-π/6)怎么化简,
-
化简sinx+sin(x+2π/3)+cos(x+5π/6)
-
化简cos(2π/3-x)+cos(2π/3+x)+cosx