Question

初二一道数学题,求高人.2/(9-3a),(a-1)/(a²-3-2a),a/(a²-5a+6)分式

Answer 1

∵9-3a=-3(a-3) a²-3-2a=(a-3)(a+1) a²-5a+6=(a-2)(a-3)

∴最简公分母：3(a-3)(a-2)(a+1)

∴2/(9-3a)=-2(a-2)(a+1)/3(a-3)(a-2)(a+1)

(a-1)/(a²-3-2a)=3(a-1)(a-2)/3(a-3)(a-2)(a+1)

a/(a²-5a+6)=3a(a+1)/3(a-3)(a-2)(a+1)