方程应该是x+1/"("4x-6")"=(a*a+3a+1)/2a 吧!
展开得到x+1/(4x+6)=a/2+3/2+1/2a,就把右边3/2移左边左边,把X配成4x-6形式:(4x-6)/4+1/(4x-6)=a/2+1/2a,=>(4x-6)/2+2/(4x-6)=a+1/a
所以(4x-6)/2=a或1/a,x=(2a+6)/4或(2/a+6)/4
方程应该是x+1/"("4x-6")"=(a*a+3a+1)/2a 吧!
展开得到x+1/(4x+6)=a/2+3/2+1/2a,就把右边3/2移左边左边,把X配成4x-6形式:(4x-6)/4+1/(4x-6)=a/2+1/2a,=>(4x-6)/2+2/(4x-6)=a+1/a
所以(4x-6)/2=a或1/a,x=(2a+6)/4或(2/a+6)/4