题意为:a²+b²=6ab
又因为(a+b)²-2ab=a²+b²=6ab所以[(a+b)²=8ab]
(a-b)²+2ab=a²+b²=6ab所以[(a-b)²=4ab]
因为a大于b大于0,
所以√(a+b)²/(a-b)² =a+b/a-b =√8ab/4ab=√2
题意为:a²+b²=6ab
又因为(a+b)²-2ab=a²+b²=6ab所以[(a+b)²=8ab]
(a-b)²+2ab=a²+b²=6ab所以[(a-b)²=4ab]
因为a大于b大于0,
所以√(a+b)²/(a-b)² =a+b/a-b =√8ab/4ab=√2