10x+x^2-100=0,求x
2个回答
x^2+10x-100=0
x^2+10x=100
x^2+10x+25=125
(x+5)^2=125
x+5=±5√5
x=5√5-5 x=-5√5-5
相关问题
【 100x+10(x-2)+(26-2x) 】-【 10x+x 】=【 100(26-2x)+10(x-2)+x 】
若(2-x)^100=a0+a1x+a2x^2+……+a100x^100 求:
若(2-x)^100=a0+a1x+a2x^2+……+a100x^100 求:
100+100*2%=x-10%x+(100-x)+(100-x)*5%
0.2分之X-(6X-100)=10
[(100-x)*10%]*(1-x/100)=0.4,
已知x^2-x-1=0求100x^2-100x+9的值
(1)1-100x =(1+10x)(1-10x) (2)-0.16+a b =(ab) -0
接下列一元二次方程:如:3x^2-10x+3=0x=-(-10)±√(-10)^2-4x3x3/2X3x=10±√100
100(x+4)+10x+(x+2)=21[10x+(x+2)]