若la+b-1l+(a-b-3)^3=0
则a+b-1=0
a-b-3=0
a=2
b=-1
3a^2(a^3b^2-2a)-4a(-a^2b)^2
=3a^5b^2-6a^3-4a^5b^2
=-a^5b^2-6a^3
=-2^5×(-1)^2-6×2^3
=-32×1-6×8
=-32-48
=-80
若la+b-1l+(a-b-3)^3=0
则a+b-1=0
a-b-3=0
a=2
b=-1
3a^2(a^3b^2-2a)-4a(-a^2b)^2
=3a^5b^2-6a^3-4a^5b^2
=-a^5b^2-6a^3
=-2^5×(-1)^2-6×2^3
=-32×1-6×8
=-32-48
=-80