设M,P,N在t分钟后的坐标分别是m(t),p(t),n(t)
p(t) = -3t
m(t) = -3 - t
n(t) = 1 - 4t
P到M的距离为:|p(t)-m(t)| = |3-2t|
P到N的距离为:|p(t)-n(t)| = |t-1|
令|3-2t| = |t-1|
所以 (3-2t)^2 = (t-1)^2
化简得 3t^2 - 10t + 8 = 0
解得 t = 4/3 或 2
所以是 4/3或者2分钟之后距离相等
设M,P,N在t分钟后的坐标分别是m(t),p(t),n(t)
p(t) = -3t
m(t) = -3 - t
n(t) = 1 - 4t
P到M的距离为:|p(t)-m(t)| = |3-2t|
P到N的距离为:|p(t)-n(t)| = |t-1|
令|3-2t| = |t-1|
所以 (3-2t)^2 = (t-1)^2
化简得 3t^2 - 10t + 8 = 0
解得 t = 4/3 或 2
所以是 4/3或者2分钟之后距离相等