x^2+ax+b^2=0
方程有实数根,判别式≥0
a^2-4b^2≥0
(a+2b)(a-2b)≥0
又a,b的取值均不小于0
a≥2b
b=0时,a可取1,2,3,4
b=1时,a可取2,3,4
b=2时,a可取4
用数对(a,b)表示:
(1,0),(2,0),(3,0),(4,0),(2,1),(3,1),(4,1),(4,2)
x^2+ax+b^2=0
方程有实数根,判别式≥0
a^2-4b^2≥0
(a+2b)(a-2b)≥0
又a,b的取值均不小于0
a≥2b
b=0时,a可取1,2,3,4
b=1时,a可取2,3,4
b=2时,a可取4
用数对(a,b)表示:
(1,0),(2,0),(3,0),(4,0),(2,1),(3,1),(4,1),(4,2)