(1)由题意得:临界角C=30°则:
n=
1
sinc =
1
sin30° =2.
(2)光线b入射,由折射定律有:
sin30°
sinr =n
得:sinr=
1
4 ,
所以:OD=Rtanr=
Rsinr
1 -(sinr) 2
解得:OD=
15
15 R .
答:(1)玻璃的折射率n为2;
(2)OD的长度是
15
15 R
(1)由题意得:临界角C=30°则:
n=
1
sinc =
1
sin30° =2.
(2)光线b入射,由折射定律有:
sin30°
sinr =n
得:sinr=
1
4 ,
所以:OD=Rtanr=
Rsinr
1 -(sinr) 2
解得:OD=
15
15 R .
答:(1)玻璃的折射率n为2;
(2)OD的长度是
15
15 R