没有图,胡乱猜一个吧!
设AB=a, BE=b,
S⊿AEF=b﹙a+b﹚/2AB/AE=a/﹙a+b﹚
∵⊿ABH∽⊿AEF∴S⊿ABH/S⊿AEF=a²/﹙a+b﹚²
S⊿ABH=a²b/[2﹙a+b﹚]
S⊿AHC=a²/2-a²b/[2﹙a+b﹚]
=a³/[2﹙a+b﹚]
没有图,胡乱猜一个吧!
设AB=a, BE=b,
S⊿AEF=b﹙a+b﹚/2AB/AE=a/﹙a+b﹚
∵⊿ABH∽⊿AEF∴S⊿ABH/S⊿AEF=a²/﹙a+b﹚²
S⊿ABH=a²b/[2﹙a+b﹚]
S⊿AHC=a²/2-a²b/[2﹙a+b﹚]
=a³/[2﹙a+b﹚]