先说说下列各题的运算顺序,再用递等式计算.

1个回答

  • 解题思路:(1)按照先算括号里面的,再从左到右顺序计算即可解答,

    (2)按照先算括号里面的减法,再算乘法,最后算减法的顺序即可解答,

    (3)按照先算括号里面的除法,再算括号里面的加法,最后算乘法即可解答,

    (4)按照先算括号里面的乘法,再算括号里面的减法,最后算除法的顺序即可解答,

    (5)(6)按照先算小括号里面的,再算中括号里面的,最后算括号外面的顺序即可解答.

    (1)8507-(153-48)+5369,

    =8507-105+5369,

    =8402+5369,

    =13771;

    (2)645-45×(50-38),

    =645-45×12,

    =645-540,

    =105;

    (3)(32+360÷45)×72,

    =(32+8)×72,

    =40×72,

    =2880;

    (4)412÷(607-36×14),

    =412÷(607-504),

    =412÷103,

    =4;

    (5)[591-(134+48)]×26,

    =[591-182]×26,

    =409×26,

    =10634;

    (6)963÷[732-(496+227)],

    =963÷[732-723],

    =963÷0,

    =0.

    点评:

    本题考点: 整数四则混合运算.

    考点点评: 本题主要考查学生依据四则运算顺序正确进行计算的能力,关键是计算结果要准确.