取6 g铝土矿(含Al2O3、Fe2O3)样品,放入盛有100 mL H2SO4溶液的烧杯中,充分反应后过滤,向滤液中加

2个回答

  • Al(OH)3+OH- == (AlO2)-+ H2O

    n(AL3+)=△NaOH=10ml*10mol/L=0.1mol

    n(AL2O3)=0.05mol

    m(AL2O3)=0.05*102=5.1g

    m(Fe2O3)=6-5.1=0.9g

    Fe2O3+3H2SO4==Fe2(SO4)3+3H2O

    160294

    0.9g x1

    x1=1.65375g

    AL2O3+3H2SO4=AL2(SO4)3+3H2O

    102 294

    5.1x2

    x2=14.7g

    n(H2SO4)2=5/40 /2=0.0625mol

    x1+x2=1.65375+14.7=16.35375g

    n(H2SO4)=n1+n2=0.166875+0.0625=0.229375mol

    c(H2SO4)=0.229375mol/0.1L=2.29375mol/L