1 因为(2m-1)^2>=0所以如果1-(2m-1)^2有最大值那么2m-1=0m=1/2所以3m-1=4x-23/2-1=4x-2x=5/82 x^2和(y-1/2)^2互为相反数则x=0,y-1/2=0y=1/2因此(x^2y-3xy)-(3x^2y-2xy)=0x^2-2y+5=7那么2y-x^2=-26y-3x^2=-6所以6y...
1 因为(2m-1)^2>=0所以如果1-(2m-1)^2有最大值那么2m-1=0m=1/2所以3m-1=4x-23/2-1=4x-2x=5/82 x^2和(y-1/2)^2互为相反数则x=0,y-1/2=0y=1/2因此(x^2y-3xy)-(3x^2y-2xy)=0x^2-2y+5=7那么2y-x^2=-26y-3x^2=-6所以6y...