Question

((x+2/2x^2-3x)-(x^2+2x/2x^2+x-6))/((1/2)-(1/4x-6))

Answer 1

((x+2/2x^2-3x)-(x^2+2x/2x^2+x-6))/((1/2)-(1/4x-6))

=[(x+2)/x(2x-3)-x(x+2)/(2x-3)(x+2)]/[(2x-4)/(4x-6)]

=[(x+2)/x-x]/(x-2)

=(-x^2+x+2)/x(x-2)

=-(x-2)(x+1)/x

=-(x+1)/x