Question

将抛物线Y=-（X-2）²-4 向右平移m 在向上平移n 所得抛物线过点（-3,5）和（-1,3）两点.求m.n

Answer 1

向右平移m

y=-(x-2-m)^2-4

向上平移n

y=-(x-2-m)^2-4+n

带入两个点

-(5+m)^2-4+n=5

-25-m^2-10m-4+n=5

m^2+10m+34-n=0(1)

-(3+m)^2-4+n=3

-9-m^2-6m-4+n=3(2)

(1)+(2)

4m+21=3

m=6

n=88