Question

(t^2-2t^2-t+1)ε(t)= ; f(t-τ)*δ(t)=?; 若f(t)=2δ(t)+3τ^(-2τ)τ(t

Answer 1

f(t-1)-1=1-f(t) (t-1)^2-(t-1)+1-1=1-t^2-t+1 t^2-2t+1-t+1=2-t^2-t 2t^2+2t=0 t(t+1)=0 t=0或者t=-1