-4-1/9t^2+4/3t(a-2b)^2+6a-12b+9
3个回答
-4-1/9t^2+4/3t
=-(1/9t²-4/3t+4)
=-(1/3t-2)²
(a-2b)^2+6a-12b+9
=(a-2b)²+6(a-2b)+9
=(a-2b+3)²
相关问题
设有向量组a1=(2,21,4,3)^T,a2=(-1,1,-6,6)^T,a3=(-1,-2,2,-9)^T,a4=(
(4a^3-12a^2b^2 9ab^3)/(4a^2-9b^2)
a).[x,y,z]=[1,8,6]+s[1,-12,-12]+t[2,4,-3] b).[x,y,z]=[6,-9,-
a^2-6ab+12b+9b^2-4a
判断向量组a1=(2,1,1,0)T a2=(1,5,-4,9)T a3=(1,2-1,3)T a4(0,-3,3,6)
a^2+6ab+9b^2-4a-12b-12因式分解
因式分解:(1)(a+b)x2-(a+b);(2)9(a+b)2-4(a-b)2;(3)6xy2-9x2y-y3;(4)
(a2-4ab+4b2-6a+12b+9)怎么因式分解
(a^2-6a+9)/(4-b^2)÷(3-a)/(2+b)*(a^2)/3a-9
1.去括号(1)-(2m-3)(2)n-3(4-2m)(3)316a-8(3b+4c)(4)4t+2/3(12-9v)(