（1）∠ BAC =
（2）
(1) 由旋转得△ ACB ≌△ DEB
∴ BD = BA
∴∠ BAD = ∠ BDA =
∴∠ ABD =
∴∠ ABC = ∠ ABD =
∵∠ C =
∴∠ BAC =
·········································································· 5分
(2) ∵ BC = 8， AC = 6，∠ C =
∴
∵∠ DEB = ∠ C =
且 BE = BC = 8， DE ="AC" = 6
∴ AE =" AB" – BE = 2
在Rt△ DEA 中，
设 AD 边上的高为 h
∴
∴
······················································· 10分