n趋近于多少?
如果是n→∞.
lim【n→∞】[(2n+1)/(4n²+2n-1)]
是一个“∞/∞”型的极限,适用于洛必达法则.
lim【n→∞】[(2n+1)/(4n²+2n-1)]
=lim【n→∞】[2/(8n+2)]
=lim【n→∞】[1/(4n+1)]
=0
lim（2n+1）/（4n^2+2n-1）
1个回答
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